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10x^2+11x-22.5=0
a = 10; b = 11; c = -22.5;
Δ = b2-4ac
Δ = 112-4·10·(-22.5)
Δ = 1021
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1021}}{2*10}=\frac{-11-\sqrt{1021}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1021}}{2*10}=\frac{-11+\sqrt{1021}}{20} $
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